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430=x^2+2.4x+25
We move all terms to the left:
430-(x^2+2.4x+25)=0
We get rid of parentheses
-x^2-2.4x-25+430=0
We add all the numbers together, and all the variables
-1x^2-2.4x+405=0
a = -1; b = -2.4; c = +405;
Δ = b2-4ac
Δ = -2.42-4·(-1)·405
Δ = 1625.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{1625.76}}{2*-1}=\frac{2.4-\sqrt{1625.76}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{1625.76}}{2*-1}=\frac{2.4+\sqrt{1625.76}}{-2} $
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